7x^2/3=1200

Solution for 7x^2/3=1200 equation:

7x^2/3=1200

We move all terms to the left:

7x^2/3-(1200)=0

We multiply all the terms by the denominator


7x^2-1200*3=0

We add all the numbers together, and all the variables

7x^2-3600=0

a = 7; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·7·(-3600)
Δ = 100800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{100800}=\sqrt{14400*7}=\sqrt{14400}*\sqrt{7}=120\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{7}}{2*7}=\frac{0-120\sqrt{7}}{14}
=-\frac{120\sqrt{7}}{14}
=-\frac{60\sqrt{7}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{7}}{2*7}=\frac{0+120\sqrt{7}}{14}
=\frac{120\sqrt{7}}{14}
=\frac{60\sqrt{7}}{7}
$